Question

√3x2+10x+7√3 factorize it.

Answer 1

given: ✓3x^2+10x+7✓3
=> ✓3x2 + 7x + 3x + 7✓3
=> x(✓3x + 7)+✓3(✓3x + 7)
=> (x+✓3)(✓3x+7)

Answer 2

Answer:

The factorisation of $\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }$ will be $(\sqrt3 x+7)(x+\sqrt3)$

To find:

Factorise the given expression $\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }$

Solution:

Given,

Factorise the given expression,  

$\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }$

For factorising, splitting out the middle terms in the given expression, the middle term becomes as follows,

$= \sqrt { 3 } x ^ { 2 } + 3 x + 7 x + 7 \sqrt { 3 }$

as 7 + 3 = 10 and 7 × 3 = 21

$\begin{array} { l } { = \sqrt { 3 } x ( x + \sqrt { 3 } ) + 7 ( x + \sqrt { 3 } ) } \\\\ { = ( \sqrt { 3 } x + 7 ) ( x + \sqrt { 3 } ) } \\\\ { \sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 } = ( \sqrt { 3 } x + 7 ) ( x + \sqrt { 3 } ) } \end{array}$

Thus, the factorisation of $\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }$ will be $(\sqrt3 x+7)(x+\sqrt3)$