Question

√3x2+11x+6√3=0 find ​

Answer 1

Step-by-step explanation:

√3x2 + 11x + 6√3 = 0

⇒ √3x2 + 9x + 2x + 6√3 = 0

⇒ √3x(x + 3√3) + 2(x + 3√3) = 0

⇒ (x + 3√3)(√3x + 2) = 0

x + 3√3 = 0

or √3x + 2 = 0

⇒ x = -3√3

Or x = - 2/√3 are two roots of the equation.

Answer 2

Answer:

this is your answer for your doubt question (given at bottom side).

Step-by-step explanation:

$\sqrt{3} x ^{2} + 11x + 6 \sqrt{3 } = 0. \\ \sqrt{3} x^{2} + (9 + 2)x + 6 \sqrt{3} = 0 \\ \sqrt{3} x ^{2} + 9x + 2x + 6 \sqrt{3 } = 0. \\ \sqrt{3} x (x + 3\sqrt{3} ) + 2(x + 2 \sqrt{3} ) = 0. \\ (x + 3 \sqrt{3} )( \sqrt{3} x + 2) = 0. \\ x + 3 \sqrt{3} = 0 \\ \sqrt{3}x + 2 = 0. \\ x = - 3 \sqrt{3} \: and \: - (2 \div \sqrt3 ).$

I think it is standard and satisfying answer for your mind and heart.

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