Question

3x²+13x-10 by factorisation
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Answer 1

Answer:

(3x - 2) (x + 5)

Step-by-step explanation:

We need to factorize 3x²+13x-10 using factorization method

3x²+13x-10 = 3x² + 15x - 2x -10

= 3x (x + 5) - 2 (x + 5)

= (3x - 2) (x + 5)

So, the factors of 3x²+13x-10 are (3x - 2) (x + 5).

Further you can also find the value of x by equating both the factors individually to 0.

3x - 2 = 0                                                         x+5 = 0

x = 2/3                                                             x = -5

Answer 2

Answer:

On factorizing $3x^{2} +13x -10$ we get  factors as $( 3x - 2 ) (x + 5)$ and value of

$x$ as , $x =\frac{2}{3}$ or  $x = -5$ .

Step-by-step explanation:

To solve : given expression by factorization

Given expression : $3x^{2} +13x -10$

Solution :

• According to question we are asked to factorize given expression .
• We factorize given expression by  splitting the middle term of expression .  
• We spilt the middle term such that product of the numbers is last term and sum or difference of those numbers is middle term.
• Here, $13x$ is the middle term and by multiplying constant of first and last term we get last term as $-30x$ .

        $\begin{array}{l}=3x^{2}+13x -10 \\\\=3x^{2} + 15x -2x -10 \\\\= 3x(x+5)-2(x+5) \\\\=(3x -2)(x + 5) \\\\x =\frac{2}{3} \text { or } x=-5\end{array}$

Note :

Question for above solution is : solve $3x^{2} +13x -10$ by factorization  .