Question

3x² + 17x + 14 factorise

Answer 1

$\textbf{ QUESTION}$

Factorisation of 3x² + 17x + 14

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$\textbf{ SOLUTION}$

${3x}^{2} + 17x + 14 \\ \\=> 3 {x}^{2} + (3 + 14)x + 14 \\ \\=> 3 {x}^{2} + 3x + 14x + 14 \\ \\=> 3x(x + 1) + 14(x + 1) \\ \\=> (x + 1)(3x + 14)$

$\textbf{ (x + 1)(3x + 14) are the factors of}$
3x² + 17x + 14

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$\huge\bold{ Thanks..}$

Answer 2

Question=3x²+17x+14

I know When You Asking This Question You Have Many Doubts In it.I will try to clear it.

Firstly What You have to do when You See this Type of question.Firstly Add First term with Last Term And forget X
Then 3+14=17

As You See 17 is also in Middle
So we can split it as 14+3
It is called 'Middle Term Splitting'

Then Now Write This

3x²+14x+3x+14
Now Separate in 2 -2 terms
(3x²+14x)+(3x+14)
Now What we common in both in 1st it's X and in Second it's 1
So write
X(3x+14)+1(3x+14)
As you see two terms are same Write them As 1 term and others left as one term.
You will get
(3x+14)(X+1)

Factors=(3x+14)(X+1)

Now When you multiply it you will Question as Product..