Question

3x²+18x+27=0
find roots​

Answer 1

Answer:

Step-by-step explanation:

3x^2+9x+9x+27=0

3x(x+3)+9(x+3)=0

(3x+9)(x+3)=0

3x+9=0,x+3=0

3x=-9,x=-3

x=-3

Answer 2

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a}$

$discriminant= \sqrt{324 - 324} = 0$

$x = \frac{ - 18}{6} = - 3$

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