√3x2-2√2x-2√3=0 by completing squares
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x=−(−2√2)±√((−2√2)2–4×√3×(−2√3))2√3
=2√2±√(8+24)2√3
=2√2±4√22√3=2√2(1±2)2√3=√2(1±2)√3
⟹x=3√2√3 or x=−√2√3
⟹x=√3√2 or x=−√(23)
⟹x=√6 or x=−√(23)
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