√3x² – 2√2x – 2√3 = 0....
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√3x²-3√2x+√2x-2√3x=0
=> √3x(x-√6)+√2(x-√6)=0
=> (√3x+√2)(x-√6)=0
=> (√3x+√2)=0 or (x-√6)=0
=> x=-√2/√3 or x=√6
parasakare:
great answer
thanks
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