Math, asked by geetapathrabe4, 11 hours ago

√3x² - 2√2x - 2√3 = 0 find the value of discriminant

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Answered by sahilshet294
0

32

Step-by-step explanation:

√3x² - 2√2x - 2√3 = 0

compare the given equation with

ax² + bx + c = 0

therefore, a = √3 , b = -2√2 , c = -2√3

Discriminant(∆) = b² – 4ac

= (-2√2)² – 4 × (√3) × (-2√3)

= 4×2 + 8×3

= 8 + 24

therefore, ∆ = 32

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