Question

√3x2- 2√2x-2√3=0 solve ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

• $\sqrt{3} {x}^{2} - 2 \sqrt{2}x - 2 \sqrt{3} = 0$

• $\sqrt{3} {x}^{2} - 3 \sqrt{2} x + \sqrt{2} x - 2 \sqrt{3 } = 0$
• $\sqrt{3} x(x - \sqrt{6} ) + \sqrt{2} (x - \sqrt{6} ) = 0$
• $= > (x - \sqrt{6} )( \sqrt{3} x + \sqrt{2} ) = 0$
• Then,
• $x = \sqrt{6} \: \: \: and \: \: \: x = \frac{ \sqrt{2} }{ \sqrt{3} }$
• Hence the required answer. I hope it will help you. Thank you