Question

√3x²-2√2x-2√3=0 solve for x​

Answer 1

Given

√3x²-2√2x-2√3=0

solve for x

Solution

→ √3x² - 2√2x - 2√3 = 0

★ Solve by splitting middle term

→ √3x² - 3√2x + √2x - 2√3 = 0

→ √3x(x - √6) + √2(x - √6) = 0

→ (x - √6)(√3x + √2) = 0

Either

→ (x - √6) = 0

→ x = √6

Or

→ (√3x + √2) = 0

→ √3x = - √2

→ x = -√2/√3

Hence, √6 and -√2/√3 are the roots of given equation

Answer 2

Answer:

hey answer is given in photo

pls mark as branielist