√3x²-2√2x-2√3=0 solve for x
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Given
√3x²-2√2x-2√3=0
solve for x
Solution
→ √3x² - 2√2x - 2√3 = 0
★ Solve by splitting middle term
→ √3x² - 3√2x + √2x - 2√3 = 0
→ √3x(x - √6) + √2(x - √6) = 0
→ (x - √6)(√3x + √2) = 0
Either
→ (x - √6) = 0
→ x = √6
Or
→ (√3x + √2) = 0
→ √3x = - √2
→ x = -√2/√3
Hence, √6 and -√2/√3 are the roots of given equation
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