Question

√3x² +2√3x – 2√3 = 0

differentiation??​

Answer 1

Answer:

${x}^{2} \sqrt{3} + 2x \sqrt{3} - 2 \sqrt{3} = 0$

$\: product \: of \: \: zeros \: = \frac{c}{a} = \frac{2 \sqrt{3} }{ \sqrt{3} }$

$= 2$

$sum \: of \: zeros \: = \frac{ - b}{a} = \frac{- 2 \sqrt{3} }{ \sqrt{3} }$

$= - 2$

Answer 2

Step-by-step explanation:

We have,

$\sf\dfrac{d}{dx}(\sqrt{3}x^2+2\sqrt{3}x-2\sqrt{3}))$

$\sf\dfrac{d}{dx}(\sqrt{3}x^2)+\dfrac{d}{dx}(2\sqrt{3}x)-\dfrac{d}{dx}(2\sqrt{3})$

$\sf= 2\sqrt{3}x+2\sqrt{3}$