Question

3x2+2√5x-5=0by quadartic formula​

Answer 1

I hope this will help you......✌️

Answer 2

$\huge\green{\boxed{\green{\mathfrak{\fcolorbox{red}{black}{\underline{\pink{An}\blue{s}\purple{we}\orange{r}\red{:}\green{-}}}}}}}$

Given:-

$3 {x}^{2} +2√5x-5=0$

• It is a quadratic equations
• it means there are 2 values of X
• a= 3
• b= 2√5
• c= -5

To Find:-

The Value of x

For Information:-

a quadratic equation is any equation that can be rearranged in standard form as ax^{2}+bx+c=0 where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0.

• D= b²- 4ac
• $x = \frac{ - b ± \sqrt{d} }{2a}$

Solution:-

$3 {x}^{2} +2√5x-5=0$

• Now, we will Find the Discriminaant(D)

$D = {(2 \sqrt{5}) }^{2} - 4 \times 3 \times - 5$

$= > D = 4 \times 5 + 20 \times 3$

$= > D = 20 + 60$

$= > D = 80$

Because D>0

Therefore, There are real roots.

Now,

• We will find the value of X

$x = \frac{ - 2 \sqrt{5}± \sqrt{80} }{2 \times 3}$

$= > x = \frac{ - 2 \sqrt{5}±4 \sqrt{5} }{6}$

$= > x = \frac{ - 2 \sqrt{5} - 4 \sqrt{5} }{6} or \: x = \frac{ - 2 \sqrt{5} + 4 \sqrt{5} }{6}$

$= > x = \frac{ - 6 \sqrt{5} }{6} or \: x = \frac{ + 2 \sqrt{5} }{6}$

$= > x = - \sqrt{5} \: or \: x = \frac{ \sqrt{5} }{3}$