Question

3x² - 2√6x + 2 = 0 by sudarshan chari method​

Answer 1

Answer

The value of x is $\sqrt{2/3}$

Step-by-step explanation:

Given, equation is

                        3$x^{2}$ -2 $\sqrt{6}$x + 2 = 0

We need to find the value of x by Sridharacharya formula.

Sol: by the Sridharacharya formula,

                     x = [ - b ± $\sqrt{b^{2} - 4ac }$]/2a

                     x = [- (-2$\sqrt{6}$) ± $\sqrt{(-2\sqrt{6} )^{2} - 24 }$]/6

                     x = [ 2$\sqrt{6}$ ± $\sqrt{24 - 24}$}/6

                     x = 2$\sqrt{6}$ /6

                     x = $\sqrt{2/3}$

Thus, the value of x is equal to $\sqrt{2/3}$.