Question

3x²-2√6x+2=0
solve this by factorisation method​

Answer 1

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$3x {}^{2} - 2 \sqrt{6} x + 2 = 0 \\ 3x {}^{2} - \sqrt{6} x - \sqrt{6} x + 2 = 0 \\ \sqrt{3} x( \sqrt{3} x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3x} - \sqrt{2} ) = 0 \\ ( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) = 0 \\ \\ therefore \\ x = \frac{ \sqrt{2} }{ \sqrt{3} }$