3x²-20x-63 solve by factor
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Answered by
3
3x² - 20x - 63
= 3x² - 27x + 7x - 63
= 3x (x-9) + 7 (x-9)
=(3x + 7)(x-9)
⇒x = -7/3
or x = 9
= 3x² - 27x + 7x - 63
= 3x (x-9) + 7 (x-9)
=(3x + 7)(x-9)
⇒x = -7/3
or x = 9
Phillipe:
mark brainliest plz!!!
I think wrong because I want 2number if we multiple will 189and if we do Addison will 20
so 27*7= 189 and -27+7=-20
it's correct
plz mark brainliest, plzzzzzzzzzzzzzzzzzzzzzzz
to solve it (3x+7)(x-9) =0
then 3x+7 =0 or x-9 =0
therefore x= -7/4 or x=9
sorry x= -7/3 or x=9
do the corrections
Answered by
4
3x^2-20x-63
=3x^2-27x+7x-63
=3x(x-9)+7(x-9)
=(x-9)(3x+7) [taking (x-9) common]
Now we can say,
(x-9)(3x+7)=0
(x-9)=0
or,(3x+7)=0
the answer should be
x=9
or,x=-7/3
=3x^2-27x+7x-63
=3x(x-9)+7(x-9)
=(x-9)(3x+7) [taking (x-9) common]
Now we can say,
(x-9)(3x+7)=0
(x-9)=0
or,(3x+7)=0
the answer should be
x=9
or,x=-7/3
But its how my textbook did it.
onle expression is given
Is it right now?
we changed expression in to factors
I have corrected it.Is it right?
if we solve it we must write equal to zero
Thanks I understand.
u include this to solve the above
nice
Is it right now?
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