Question

3x²+2kx-4 has one zero negative of the other. Find the value of k.​

Answer 1

Answer:

Step-by-step explanation:hope this helps u plz mark me as the brainliest and follow me

Answer 2

Step-by-step explanation:

let the zeroes be 'a' and 'b'

but it is given that both zeroes are negative to each other

so,

a= -(b)

or b = -(a)

and we know that a + b = -(coeff. of x)/(coeff. of x²)

so,

a+(-a)=-2kx/3

0=-2kx

so k=0

for zeroes

for zeroesput k=0

for zeroesput k=0so the equation is 3x²-4

for zeroesput k=0so the equation is 3x²-4so for zeroes 3x²-4=0

for zeroesput k=0so the equation is 3x²-4so for zeroes 3x²-4=03x²=4

x²=4/3

so x=plus minus 2/√3

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