Question

3x² - 2root 6x +2 splitting the middle term ​

Answer 1

Here's your answer mark as brainliest pls

Answer 2

$\bold{ {3x}^{2} - 2 \sqrt{6x} + 2 = 0}$

$\bold{ \sqrt{3x} ( \sqrt{3x} - \sqrt{2} ) - \sqrt{2} ( \sqrt{3x} - \sqrt{2} ) = 0}$

$\bold{( \sqrt{3x} - \sqrt{2} )( \sqrt{3x} - \sqrt{2}) = 0}$

$\bold{ \sqrt{3x} = \sqrt{2} }$

$\bold{ \sqrt{3x} =- \sqrt{2}}$

$\bold{x = \frac{ \sqrt{2} }{ \sqrt{3} }}$

$\bold{other \: root}$

$\bold{ \sqrt{3x} - \sqrt{2} = 0}$

$\bold{ \sqrt{3x} =- \sqrt{2}}$

$\bold{x = \frac{ \sqrt{2} }{ \sqrt{3} }}$

Thanks!!!