Question

3x²-2root6+2 solve by quardatic formula

Answer 1

${3x}^{2} - 2 \sqrt{6} x + 2 = 0 \\ = > {3x}^{2} - \sqrt{6}x - \sqrt{6} x + 2 = 0 \\ = > \sqrt{3} x( \sqrt{3} x - \sqrt{2}) - \sqrt{2} ( \sqrt{3} x - \sqrt{2} ) \\ = > ( \sqrt{3} x - \sqrt{2} )( \sqrt{3} x - \sqrt{2} ) \\ = > \sqrt{3} x - \sqrt{2} = 0 \: or \: \sqrt{3} x - \sqrt{2} = 0 \\ = > \sqrt{3} x = \sqrt{2} \: or \: \sqrt{3} x = \sqrt{2} \\ = > x = \frac{ \sqrt{2} }{ \sqrt{3} } \: or \: x = \frac{ \sqrt{2} }{ \sqrt{3} } \: ans...$

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