3x2-2rootx+2=0 find the roots
brunoconti:
send a pic of the question instead
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√3 x^2 - 2√2 x - 2√3=0
√3 x^2 - 3√2 x + √2x -2√3 =0
√3 x(x- √6) + √2(x- √6)=0
(√3 x + √2)(x - √6)=0
x = -√2/√3 or √6
√3 x^2 - 3√2 x + √2x -2√3 =0
√3 x(x- √6) + √2(x- √6)=0
(√3 x + √2)(x - √6)=0
x = -√2/√3 or √6
tq
It is 2/x not 2/2 x
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