Question

3x2+2x+11 find minimum and maximum

Answer 1

Answer:

Let f(x)=ax2+bx+c

Compare the given Equation with f(x)

Aftercomparison

a=3;b=2;c=3

The point at which minimum value of any quadritic Equation exists obtained by -b/2a

x=−b/2a

x=−2/(2∗3)

x=−1/3

At x = - 1/3 we will obtain the minimum value of Q.E

y=3∗(−1/3)2+2∗(−1/3)+3

y=3∗1/9−2/3+3

y=1/3−2/3+3

y=3−1/3

y=(9−1)/3

y=8/3

Minimum value of Q.E is ( 8/3)

Step-by-step explanation:

Hope it helps you ✌️