3x²+2x+15=0 then find X=?
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Answered by
1
a=3 b=2 c=15
apply this formula u get
= -b+-√b^2-4ac/2a
u get
apply this formula u get
= -b+-√b^2-4ac/2a
u get
SitakantPinku:
i can't understand
Answered by
0
Given 3x^2 + 2x + 15 = 0 can be written as
3x^2 + 2x = -15
x^2 + 2x/3 = -5
Multiply (1/3) on both sides.
x^2 + 2x/3 + 1/3 = -5 + (1/3)^2
x^2 + 2x/3 + 1/3 = -5 + 1/9
x^2 + 2x/3 + 1/3 = -44/9
(x + 1/3)^2 = -44/9
x + 1/3 = root -44/root 9
x + 1/3 = root -1 * root 44/root 9
x + 1/3 = i root 44/root 9
x + 1/3 = i root 44/3
x + 1/3 = i 2 root11/3
x = -1+2i root11/3 (or) -1 - 2iroot11/3.
Hope this helps!
3x^2 + 2x = -15
x^2 + 2x/3 = -5
Multiply (1/3) on both sides.
x^2 + 2x/3 + 1/3 = -5 + (1/3)^2
x^2 + 2x/3 + 1/3 = -5 + 1/9
x^2 + 2x/3 + 1/3 = -44/9
(x + 1/3)^2 = -44/9
x + 1/3 = root -44/root 9
x + 1/3 = root -1 * root 44/root 9
x + 1/3 = i root 44/root 9
x + 1/3 = i root 44/3
x + 1/3 = i 2 root11/3
x = -1+2i root11/3 (or) -1 - 2iroot11/3.
Hope this helps!
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