Question

3x²+2x-y=5 solve the problem ​

Answer 1

$\huge{\boxed{\sf{SOLUTION-}}}$

This can be solved by the process of spitting of the middle terms.

Given,

${3x}^{2} + 2x - y = 5$

${3x}^{2} + (3 - 1)x - y = 5$

${3x}^{2} + 3x - x - y = 5$

Now find the common term

$3x(x + 1) - 1(x + y)$

$(x + 1)(3x - 1)$

Now,

$x + 1 = 0 \\ x = - 1$

And,

$3x - 1 = 0 \\ 3x = 1 \\ x = \frac{1}{3}$

$hence \: the \: required \: aswers \: are \: 1 \: and \: \frac{1}{3}$