3x²+2y-7=0:4x+y-6=0.by substitution method
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4x+y=6
y=6-4x-—--------1
Substitute 1
3x^2+2y-7=0
3x^2+2(6-4x)-7=0
3x^2+12-8x-7=0
3x^2-8x+5=0
3x^2-3x-5x+5=0
3x(x-1)-5(x-1)=0
(x-1) (3x-5)=0
x=1. x=5/3
When x=1. When x=5/3
4x+y=6. 4x+y=6
y=2. y=-2/3
Hope it helped you
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y=6-4x-—--------1
Substitute 1
3x^2+2y-7=0
3x^2+2(6-4x)-7=0
3x^2+12-8x-7=0
3x^2-8x+5=0
3x^2-3x-5x+5=0
3x(x-1)-5(x-1)=0
(x-1) (3x-5)=0
x=1. x=5/3
When x=1. When x=5/3
4x+y=6. 4x+y=6
y=2. y=-2/3
Hope it helped you
Plzz mark me as brainlist
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