Question

3x²+ 2y²+3z² if x=0,y=1, z=3​

Answer 1

${3x}^{2} + {2y}^{2} + {3z}^{2}$

$value \: we \: have \: x = 0 \: y = 1 \: z = 3$

${3(0)}^{2} + {2(1)}^{2} + {3(3)}^{2}$

$= 0 + 2 + 27$

$=29$