3x²-3√2x+1 factorise
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3x² -3√2 x +1
by discriminant method
x = {-b ± √b²-4ac } / 2a
x= {3√2 ± √ 18-12 }/ 6
x= {3√2 ± √6 } /6
so the roots will be
x = 3√2 +√6 3√2 - √6
--------------. and. -------------
6. 6
hence factors will be
{x- (3√2+√6)/6}{x+ (3√2+√6)/6
hope it helps you
Answered by
5
Hope it will help you
best of luck
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