Question

3x²+3y²+1-6xy+2√3y-2√3x


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Answer 1

Answer:

9x² + 6xy + y² = (3x)² + 2 x 3x x y + y² [(a + b)² = a² + b² - ab] = (3x + y)² (ii) 4y² – 4y ... (ii) 2x² + y² + 8z² – 2√2 xy + 4√2 yz – 8xz ... (i) (2x + 1)³ , (ii) (2a – 3b)³, (iii) [3x/2 + 1]³, (iv) [x - 2y/3]³.

Answer 2

use an identity which is:

(a square + b square + c square plus 2ab + 2bc + 2ac)

because (-6xy) and (-2 root 3x) both of them are negative what they have in common is they both have (x) so when we expand the form the (abc) which is (3x square+ 3y square + 1) becomes :

( - root 3x square + root 3y square + 1 square)

we have to make (root 3x square) to ( - root 3x square) as the other polynomials with - have both x in common.