Math, asked by anonymous937, 2 months ago

3x2+3y2-2z2+sqrt (xyz) find the value of x where y is 67382992920 and z is 6378272838829201​

Answers

Answered by Anonymous
4

Answer:

hello

You can’t. It’s a single equation in three unknowns (x, y and z). The equation doesn't constrain the values of x, y and z to unique numbers. For that, you need one equation per unknown.

If you are looking for triples of values (one for each of x, y and z) you can find triples of values that satisfy it. For each combination (x*, y*), there is a value of x* that satisfies it. But that’s not what is generally meant by “solve...

Answered by Anonymous
0

You can’t. It’s a single equation in three unknowns (x, y and z). The equation doesn't constrain the values of x, y and z to unique numbers. For that, you need one equation per unknown.

If you are looking for triples of values (one for each of x, y and z) you can find triples of values that satisfy it. For each combination (x*, y*), there is a value of x* that satisfies it. But that’s not what is generally meant by “solve.

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