Question

3x2-4√2x+1=0 solve by formula method

Answer 1

Step-by-step explanation:

$3x^{2} -4 \sqrt{2}x+1=0$

using quadratic formula,

$x = \frac{ - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}$

=> $x = \frac{ - (-4 \sqrt{2} )\pm \sqrt{ {(4 \sqrt{2} )}^{2} - 4(3)(1) } }{2(3)}$

=> $x = \frac{ 4 \sqrt{2} \pm \sqrt{ 32- 12 } }{6}$

=> $x = \frac{4 \sqrt{2}\pm \sqrt{20} }{6}$

=> $x = \frac{4 \sqrt{2}\pm 2 \sqrt{5} }{6}$

=> $x = \frac{2(2 \sqrt{2} \pm \sqrt{5} )}{6}$

=> $\boxed{x = \frac{2 \sqrt{2} + \sqrt{5} }{3} }$

=> $\boxed{x = \frac{2 \sqrt{2} - \sqrt{5} }{3} }$