Question

3x2-4√3x+4=0 find the nature of the quadratic equation

Answer 1

Answer:

roots are real and equal

Step-by-step explanation:

Comparing the equation with

ax^2 + bx + c = 0. we get,

a = 3. b = - 4√3. c =4

discriminant = b^2 - 4ac

= ( - 4√3 )^2 - 4 (3) (4)

= 48 - 48

= 0

i.e D = 0

roots are real and equal