3x²-4√3x+4=0 find the nature of the roots of the quadratic equation and solve it
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Answer:
Step-by-step explanation:
the nature of roots can be equal, real and imaginary
in order to find that we use determinant formula
=b^2-4*a*c
if determinant is zero roots are equal
if determinant is > 0 then roots are real and distinct
if determinant is <0 roots are imginary
now in the given equation find
b=-4sqrt(3)
a=3
c=4
4*a*c=4*3*4=48
b^2=(4*sqrt(3))^2=48
difference=0
so roots are equal
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