Question

3x2+4x+1=0. find the value of x using factorization method​

Answer 1

Answer:

${3x}^{2} + 4x + 1 = 0$

${3x}^{2} + 3x + 1x + 1 = 0$

$3x(x + 1) + 1(x + 1) = 0$

$(3x + 1)(x + 1) = 0$

$3x + 1 = 0$

$x = \frac{ - 1}{3}$

or

$x + 1 = 0$

$x = - 1$

$x = \frac{ - 1}{3} (or)x = - 1$

Answer 2

$\huge\underline{Answer:-}$

$\bf{Either \:x = -1 or \:x = -1/3}$

$\huge\bold{Given:-}$

↦ $\bf{3x² + 4x + 1 = 0}$

$\bf{Now , doing \:middle \:term , we \:get}$

⇒ $\bf{3x² + ( 3 + 1 ) x + 1 = 0}$

⇒ $\bf{3x² + 3x + x +1 = 0}$

⇒ $\bf{3x ( x + 1 ) + 1 ( x + 1 ) = 0}$

⇒$\bf{( x + 1 ) ( 3x + 1) = 0}$

$\bf{Either,}$

↦ $\bf{( x + 1 ) = 0}$

⇒ $\bf{x = -1}$

$\bf{Or,}$

↦ $\bf{( 3x + 1) = 0}$

⇒ $\bf{3x = -1}$

⇒ $\bf{x = -1/3}$