Question

3x2+4x-1 find the zeroes of the polynomial

Answer 1

$\huge{\underline{\overline{\mathbf{<strong>Answer</strong>}}}}$

⇒$\Large{3x^2+4x-1}$

⇒$3x^2+3x-x-1$

⇒$3x(x+1)-1(x+1)$

⇒$\Large{(3x-1)(x+1)}$

First Zero:

→$3x-1=0$

→$3x=1$

• $\huge{\pink{\underline{x=\frac{1}{3}}}}$

Second Zero:

→$x-1=0$

• $\huge{\pink{\underline{x=1}}}$

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