Question

√3x²+4x-7√3=0 by factorisatio. method​

Answer 1

Answer:

$\sqrt{3} {x}^{2} + 7x - 3x - 7 \sqrt{3} = 0 \\ x( \sqrt{3} x + 7) - \sqrt{3} ( \sqrt{3} x + 7) = 0 \\ ( \sqrt{3} x + 7)(x - \sqrt{3} ) = 0 \\ x = - 7 by \sqrt{3} \\ and \: x = \sqrt{3}$