Question

(3x2 + 4x – 7)(8 – 2x + x2)​

Answer 1

Answer:

(3x^2+4x-7)(8-2x+x^2)

=24x^2-6x^3+3x^4+32x-8x^2+4x^3-56+14x-7x^2

=3x^4-2x^3+9x^2+46x-56

Answer 2

(3x² + 4x – 7)(8 – 2x + x²)

= 3x² × 8 + 3x² × (-2x) + 3x² × x² + 4x × 8 + 4x × ( -2x) + 4x × x² - 7 × 8 - 7 (-2x) - 7 × x²

= 24x² - 6x³ + 4x⁴ + 32x - 8x² +5x³- 56 - 14x - 7x²

=24x² - 7x² - 8x² -6x³ + 5x³ + 4x⁴ + 32x - 14x + 56

= 9x² - x³ + 4x⁴ + 18x + 56

= 4x⁴ - x³ + 9x² + 18x + 56