-3x²-4xy+2y² whats the answer.
Answers
Answer:Hi
Step-by-step explanation: This is considered a quadratic equation because the highest power is 2. There are a couple ways of solving this that I'll show you. The first deals with bringing all of the terms over to one side. I'll bring the 5y to the left so the 2y2 can stay positive. Now we have
2y2 - 5y = 0 From this we can factor a y out and get y(2y-5) = 0
Now think back to multiplication to get to 0. If one term is equal to zero then the product is equal to zero. In this case, either y equals zero since 0*(20-5) = 0 or 2y-5 equals zero since y0 = 0. This already gave us one answer, which is y = 0. To find the other answer simply set 2y-5 = 0. When we solve we get y = 2.5. These are our two answers.
Another way we can solve this is through the quadratic equation. This is solutions = (-b ± √(b2 - 4ac))/(2a)
This is under the assumption that the generic quadratic equation is ax2 + bx + c. In this case we have 2y2 - 5y + 0 so a = 2, b = -5, and c = 0. let's plug in:
(-b ± √(b2 - 4ac))/(2a) =
(--5 ± √((-5)2 - 420))/(2*2) =
(5 ± √(25 - 0))/(4) =
(5 ± 5)/(4) = 10/4 = 2.5 OR 0/4 = 0.
Both methods give you the same answers. Good luck and let me know if anything is unclear.
Answer:
Step-by-step explanation:
No like terms so the answer is
-(3x2+4xy-2y2)