Question

(3x²+4y) ×(2x+3y) please explain this​

Answer 1

Answer:

$6x^3+9x^2y+6xy+12y^2$

Step-by-step explanation:

Let us multiply $(3x^2+4y)*(2x+3y)$

$(a+b)*(c+d)=ac+ab+bc+bd$

So applying the equation above to the question, we get

$(3x^2+4y)*(2x+3y)=6x^3+9x^2y+6xy+12y^2$

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