3x²-56x+140
find value of x
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3x²-56x+140=0
x=[-b+-√(b²-4ac)]/2a
= {-(-56)+-√[(-56)²-4(3)(140)]}/2(3)
=[56+-√(3136-1680)]/6
x =[56+-√1456]/6
x=(56+√1456)/6 or x=(56-√1456)/6
x=[-b+-√(b²-4ac)]/2a
= {-(-56)+-√[(-56)²-4(3)(140)]}/2(3)
=[56+-√(3136-1680)]/6
x =[56+-√1456]/6
x=(56+√1456)/6 or x=(56-√1456)/6
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