Math, asked by vjariwala6969, 16 hours ago

3x2-5y-2-5y-3x2+xy y=1,x=2

Answers

Answered by udgirkar67
0

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=>5y−3x²+xy−3x²−5y−2

= > 5y - 5y - 3x² - 3x² + xy - 2=>5y−5y−3x²−3x²+xy−2

= > { - 6x}^{2} + xy - 2=>−6x

2

+xy−2

Now , put the value

• x = 2

• y = 1

= > { - 6x}^{2} + xy - 2=>−6x

2

+xy−2

= > - 6 \times 2 × -6 × 2 + 2 \times 1 - 2=>−6×2×−6×2+2×1−2

=> -12 × (-12) + 2 - 2

=> 12 × 12 +2 -2

=> 144

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