Question

3x2+6x+3 = 0 then the roots of the equations are​

Answer 1

Answer:

3x2 - 6x) - 3 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

3x2 - 6x - 3 = 3 • (x2 - 2x - 1)

Trying to factor by splitting the middle term

3.2 Factoring x2 - 2x - 1

The first term is, x2 its coefficient is 1 .

The middle term is, -2x its coefficient is -2 .

The last term, "the constant", is -1

Step-1 : Multiply the coefficient of the first term by the constant 1 • -1 = -1

Step-2 : Find two factors of -1 whose sum equals the coefficient of the middle term, which is -2 .

-1 + 1 = 0

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

3

:

3 • (x2 - 2x - 1) = 0

Answer 2

Answer:

3x² + 6x + 3 = 0

here a = 3, b=6 , c= 3

$\alpha \beta are \: \: zeroes$

alpha = -b/ a

= -6/3

= -2

beta = c/a

= 3/3

= 1

Therefore roots are -2 and 1