Question

3x²+8y²+16xy+7-(10xy+4x²-13+9y²)
pls solve step by step ​

Answer 1

Answer:

3x

2

−4y

2

+5xy+20−q=−x

2

−y

2

+6xy+20

⇒q=3x

2

−4y

2

+5xy+20−(−x

2

−y

2

+6xy+20)

⇒q=3x

2

−4y

2

+5xy+20+x

2

+y

2

−6xy−20

⇒q=3x

2

+x

2

−4y

2

+y

2

+5xy−6xy+20−20

⇒q=4x

2

−3y

2

−xy+0

Hence, 4x

2

−3y

2

−xy should be subtracted.

Step-by-step explanation:

make me brilliant

Answer 2

solution↓

$3x {}^{2} + 8y {}^{2} + 16xy + 7 - (10xy + 4x {}^{2} - 13 + 9y {}^{2})$

solve bracket now mines add in so pogitive value negative and negative value pogitive

$3x {}^{2} + 8y {}^{2} + 16xy + 7 - 10xy - 4x {}^{2} + 13 - 9y {}^{2}$

now add and subscrate exact matches value

$- x {}^{2} - y {}^{2} + 6xy + 20$

take mines common

$- (x {}^{2} + y {}^{2} - 6xy - 20)$

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I hope it helps you