Math, asked by harshitdhanuka5787, 11 months ago

3x2-px+3=0 find the value of p if the equation has real roots and p>0

Answers

Answered by mysticd
2

Anawer'

p > 6

Explanation:

Compare 3x²-px+3=0 with

ax²+bx+c=0 , we get

a=3,b=-p, c = 3

Discreminant (D)>0

[ Given , roots are real ]

=> b²-4ac >0

=> (-p)²-4×3×3 >0

=> p² -36>0

=> p² > 36

=> p > √36

=> p >6

•••

Answered by GodlyGreNinja
2

Answer:

Compare 3x²-px+3=0 with

ax²+bx+c=0 , we get

a=3,b=-p, c = 3

Discriminant (D)>0

[ Given , roots are real ]

=> b²-4ac >0

=> (-p)²-4×3×3 >0

=> p² -36>0

=> p² > 36

=> p > √36

=> p ≥ ±6

=> p ≥ 6 or p ≤ -6

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