3x2-px+3=0 find the value of p if the equation has real roots and p>0
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Answered by
2
Anawer'
p > 6
Explanation:
Compare 3x²-px+3=0 with
ax²+bx+c=0 , we get
a=3,b=-p, c = 3
Discreminant (D)>0
[ Given , roots are real ]
=> b²-4ac >0
=> (-p)²-4×3×3 >0
=> p² -36>0
=> p² > 36
=> p > √36
=> p >6
•••
Answered by
2
Answer:
Compare 3x²-px+3=0 with
ax²+bx+c=0 , we get
a=3,b=-p, c = 3
Discriminant (D)>0
[ Given , roots are real ]
=> b²-4ac >0
=> (-p)²-4×3×3 >0
=> p² -36>0
=> p² > 36
=> p > √36
=> p ≥ ±6
=> p ≥ 6 or p ≤ -6
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