3x²+x-12 find zeroes by all three methods
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Answered by
0
Answer:
x = 2/3, x = -1.
Step-by-step explanation:
To find the zeros of the polynomial
3x² + x - 12
By splitting the middle term,
3x² + 3x - 2x - 2= 0
3x (x + 1) - 2 (x + 1)= 0
(3x - 2) (x + 1) =0
So, x = 2/3,. x = -1.
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Answered by
1
Step-by-step explanation:
x= 2/3 and X = -1...
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