Question

3x²+x-2
Find the zeros of the polynomial

Answer 1

Answer:

Question :-

Find the zeros of the polynomial 3x²+x-2

Required Answer :-

2/3 and -1 are the zeroes of the polynomial 3x² + x - 2

By Splitting the middle term :-

$3 {x}^{2} + x - 2$

${3x}^{2} + 3x - 2x - 2$

$3x(x + 1) - 2(x + 1)$

$(3x - 2)(x + 1)$

To find the zeroes we will equate this to zero.

$1. \: 3x - 2 = 0$

$3x = 2$

$x = \frac{2}{3}$

$2. \: x + 1 = 0$

$x = - 1$

Therefore the two zeroes are 2/3 and -1

Answer 2

Step-by-step explanation:

Question :-

Find the zeros of the polynomial 3x²+x-2

Required Answer :-

2/3 and -1 are the zeroes of the polynomial 3x² + x - 2

By Splitting the middle term :-

3 {x}^{2} + x - 23x

2

+x−2

{3x}^{2} + 3x - 2x - 23x

2

+3x−2x−2

3x(x + 1) - 2(x + 1)3x(x+1)−2(x+1)

(3x - 2)(x + 1)(3x−2)(x+1)

To find the zeroes we will equate this to zero.

1. \: 3x - 2 = 01.3x−2=0

3x = 23x=2

x = \frac{2}{3}x=

3

2

2. \: x + 1 = 02.x+1=0

x = - 1x=−1

Therefore the two zeroes are 2/3 and -