Question

(3x2+y2)(2x2+3y2-16)​

Answer 1

Answer:

f(x, y)=2x3 − 3x2y − 12x2 − 3y2 ... fx = 6x2 − 6xy − 24x, fy = −3x2 − 6y. To find the critical ... fxx = −24,fxy = 0,fyy = −6 =⇒ AC − B2 = ( −24)(−6) − 0 > 0 =⇒ (0,0)is local max .

Answer 2

answer

answer

I think better for you