Question

(3x2 + y2)(4x2 – 3y2) x=-1 y=-2

Answer 1

Answer:

$(3 {x}^{2} + {y}^{2} )( {4x - {3y}^{2} }) \\ = (3 \times 1 + {4}^{2} )( - 4 - 3 \times 4) \\ = 15 \times - 12 \\ = - 180$

Answer 2

Answer:

[3(1)2+(2)2][4(1)2-3(2)2]

(3×1+4)(4×1-3×4)

(4+4)(4+12)

8×16

108