Math, asked by aasha5352, 1 year ago

3x²y×(x+y+z) find the product

Answers

Answered by harendrachoubay
0

The product of 3x^{2}·y × (x + y +z) is "3x^{3}·y + 3x^{2}·y^{2} + 3x^{2}·yz".

Step-by-step explanation:

We have,

The product of 3x^{2}·y × (x + y +z)

= 3x^{2}·y × (x + y +z)

= 3x^{2}·y·x + 3x^{2}·y.y + 3x^{2}·y·z

= 3x^{3}·y + 3x^{2}·y^{2} + 3x^{2}·yz

3x^{2}·y × (x + y +z) = 3x^{3}·y + 3x^{2}·y^{2} + 3x^{2}·yz

Hence, The product of 3x^{2}·y × (x + y +z) is 3x^{3}·y + 3x^{2}·y^{2} + 3x^{2}·yz.

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