Math, asked by shankar271976, 1 month ago

(3x³ - 13/4x²y +8y³) -(7x²y+11/3x³ -14/5y³)​

Answers

Answered by sanvik225
1

Answer:

(3x³ - 13/4x²y +8y³) -(7x²y+11/3x³ -14/5y³)​

3x³ - 13/4x²y +8y³ -7x²y - 11/3x³ +14/5y³

3x³- \frac{11}{3} x^{3}- \frac{13}{4}x^{2}y -7x²y + 8y³ + \frac{14}{5}y^3

[\frac{9x^3-11x^3}{3}] + [ \frac{-13x^2y-28x^2y}{4}] + [\frac{40y^3-14y^3}{5}]

[\frac{-2x^3}{3}] + [\frac{-41x^2y}{4} ] + [\frac{26y^3}{5} ]

hope it helps

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