3x³+3x²-3x-3 if x=-2-i
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Answer:-9-3i
Step-by-step explanation:
3x^3+3x^2-3x-3
=3x^2(x+1)-3(x+1)
=(x+1)(3x^2-3)
=(x+1) 3(x^2-1)
=(x+1)3 (x+1)(x-1)
=3(x+2)^2 (x-1)
Now given x=(-2-i)
=3(-2-i+2)^2(-2-i-1)
=3(-i)^2(-3-i)
But i^2=-1
=3(-3-i)
=-9-3i
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