Question

3x3- 3x2+6x-2 if you know that two of it's zero ✓2and -✓2

Answer 1

Answer:

let x-√2=0

x=√2

x+√2=0

x=√2

(x-√2)(x+√2)

x²-(√2)²

x²-2

p(x)3x3-3x²+6x-2 divided with g(x)x²-2

x²-2)3x³-3x²+6x+2(3x-3

12x-8

p(x)= g(x)*q(x)+r(x)

x²-2*(3x-3)+( 12x+8)

3x-3+12x+8

3x+5+12x