3x³-4x²-12x+16factorise
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Answered by
1
3x³-4x²-12x+16
=x²(3x-4)-4(3x-4)
=(3x-4)(x²-4)
=(3x-4)(x-2)(x+2)
=x²(3x-4)-4(3x-4)
=(3x-4)(x²-4)
=(3x-4)(x-2)(x+2)
shobha52001:
the answer is (x-2)(x+2)(3x-4)
Thank you
Answered by
3
Given Equation is 3x^3 - 4x^2 - 12x + 16
= > (3x^3 - 4x^2) - (12x - 16)
= > x^2(3x - 4) - 4(3x - 4)
= > (x^2 - 4)(3x - 4)
= > (x^2 - 2^2)(3x - 4)
We know that a^2 - b^2 = (a + b)(a - b)
= > (x + 2)(x - 2)(3x - 4)
Hope this helps!
= > (3x^3 - 4x^2) - (12x - 16)
= > x^2(3x - 4) - 4(3x - 4)
= > (x^2 - 4)(3x - 4)
= > (x^2 - 2^2)(3x - 4)
We know that a^2 - b^2 = (a + b)(a - b)
= > (x + 2)(x - 2)(3x - 4)
Hope this helps!
:-)
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